131323040442040 has 64 divisors (see below), whose sum is σ = 301882930191360. Its totient is φ = 51401687823360.

The previous prime is 131323040441981. The next prime is 131323040442053. The reversal of 131323040442040 is 40244040323131.

It is a junction number, because it is equal to n+sod(n) for n = 131323040441993 and 131323040442011.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 176690751 + ... + 177432430.

It is an arithmetic number, because the mean of its divisors is an integer number (4716920784240).

Almost surely, 2^{131323040442040} is an apocalyptic number.

131323040442040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131323040442040 is an abundant number, since it is smaller than the sum of its proper divisors (170559889749320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131323040442040 is a wasteful number, since it uses less digits than its factorization.

131323040442040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 354123392 (or 354123388 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 131323040442040 its reverse (40244040323131), we get a palindrome (171567080765171).

The spelling of 131323040442040 in words is "one hundred thirty-one trillion, three hundred twenty-three billion, forty million, four hundred forty-two thousand, forty".