Base | Representation |
---|---|
bin | 11000011101011111… |
… | …11001101101001000 |
3 | 1020220012210222212110 |
4 | 30032233321231020 |
5 | 203343334340130 |
6 | 10011035342320 |
7 | 643301022441 |
oct | 141657715510 |
9 | 36805728773 |
10 | 13132340040 |
11 | 5629955496 |
12 | 2665bb19a0 |
13 | 1313929611 |
14 | 8c81782c8 |
15 | 51cd93ab0 |
hex | 30ebf9b48 |
13132340040 has 128 divisors (see below), whose sum is σ = 39724784640. Its totient is φ = 3472935936.
The previous prime is 13132340021. The next prime is 13132340059. The reversal of 13132340040 is 4004323131.
It is an interprime number because it is at equal distance from previous prime (13132340021) and next prime (13132340059).
It is a junction number, because it is equal to n+sod(n) for n = 13132339989 and 13132340016.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15216649 + ... + 15217511.
It is an arithmetic number, because the mean of its divisors is an integer number (310349880).
Almost surely, 213132340040 is an apocalyptic number.
13132340040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13132340040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19862392320).
13132340040 is an abundant number, since it is smaller than the sum of its proper divisors (26592444600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13132340040 is a wasteful number, since it uses less digits than its factorization.
13132340040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1783 (or 1779 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 21.
Adding to 13132340040 its reverse (4004323131), we get a palindrome (17136663171).
The spelling of 13132340040 in words is "thirteen billion, one hundred thirty-two million, three hundred forty thousand, forty".
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