Base | Representation |
---|---|
bin | 111101001001111100… |
… | …0010010001010110101 |
3 | 110112222121121110201022 |
4 | 1322103320102022311 |
5 | 4122430441232432 |
6 | 140155430110525 |
7 | 12326323533455 |
oct | 1722370221265 |
9 | 415877543638 |
10 | 131330024117 |
11 | 50773413a16 |
12 | 215521ab445 |
13 | c4cc5c2756 |
14 | 64dbda3d65 |
15 | 36399d4b12 |
hex | 1e93e122b5 |
131330024117 has 2 divisors, whose sum is σ = 131330024118. Its totient is φ = 131330024116.
The previous prime is 131330024083. The next prime is 131330024123. The reversal of 131330024117 is 711420033131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 72549961201 + 58780062916 = 269351^2 + 242446^2 .
It is a cyclic number.
It is not a de Polignac number, because 131330024117 - 26 = 131330024053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131330024017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65665012058 + 65665012059.
It is an arithmetic number, because the mean of its divisors is an integer number (65665012059).
Almost surely, 2131330024117 is an apocalyptic number.
It is an amenable number.
131330024117 is a deficient number, since it is larger than the sum of its proper divisors (1).
131330024117 is an equidigital number, since it uses as much as digits as its factorization.
131330024117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 131330024117 its reverse (711420033131), we get a palindrome (842750057248).
The spelling of 131330024117 in words is "one hundred thirty-one billion, three hundred thirty million, twenty-four thousand, one hundred seventeen".
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