Base | Representation |
---|---|
bin | 10011000111000110111… |
… | …111000001100010110100 |
3 | 11122112212101002222212102 |
4 | 103013012333001202310 |
5 | 133004121134413234 |
6 | 2443153454241232 |
7 | 163611612004430 |
oct | 23070677014264 |
9 | 4575771088772 |
10 | 1313303435444 |
11 | 466a72608140 |
12 | 19263a7b6218 |
13 | 96ac82ca830 |
14 | 477c833d9c0 |
15 | 24266d13c7e |
hex | 131c6fc18b4 |
1313303435444 has 48 divisors (see below), whose sum is σ = 3085803885696. Its totient is φ = 472316918400.
The previous prime is 1313303435429. The next prime is 1313303435453. The reversal of 1313303435444 is 4445343033131.
It is a junction number, because it is equal to n+sod(n) for n = 1313303435398 and 1313303435407.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 163994927 + ... + 164002934.
It is an arithmetic number, because the mean of its divisors is an integer number (64287580952).
Almost surely, 21313303435444 is an apocalyptic number.
1313303435444 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
1313303435444 is an abundant number, since it is smaller than the sum of its proper divisors (1772500450252).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1313303435444 is a wasteful number, since it uses less digits than its factorization.
1313303435444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 327997896 (or 327997894 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 38.
Adding to 1313303435444 its reverse (4445343033131), we get a palindrome (5758646468575).
The spelling of 1313303435444 in words is "one trillion, three hundred thirteen billion, three hundred three million, four hundred thirty-five thousand, four hundred forty-four".
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