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1313304015013 is a prime number
BaseRepresentation
bin10011000111000111000…
…001001111000010100101
311122112212102012102212221
4103013013001033002211
5133004121311440023
62443153514512341
7163611616640224
oct23070701170245
94575772172787
101313304015013
11466a72973621
1219263aa356b1
1396ac8471583
14477c8450cbb
1524266dca85d
hex131c704f0a5

1313304015013 has 2 divisors, whose sum is σ = 1313304015014. Its totient is φ = 1313304015012.

The previous prime is 1313304014977. The next prime is 1313304015017. The reversal of 1313304015013 is 3105104033131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1047261596164 + 266042418849 = 1023358^2 + 515793^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313304015013 - 29 = 1313304014501 is a prime.

It is a super-2 number, since 2×13133040150132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313304015017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656652007506 + 656652007507.

It is an arithmetic number, because the mean of its divisors is an integer number (656652007507).

Almost surely, 21313304015013 is an apocalyptic number.

It is an amenable number.

1313304015013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313304015013 is an equidigital number, since it uses as much as digits as its factorization.

1313304015013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 1313304015013 its reverse (3105104033131), we get a palindrome (4418408048144).

The spelling of 1313304015013 in words is "one trillion, three hundred thirteen billion, three hundred four million, fifteen thousand, thirteen".