Base | Representation |
---|---|
bin | 1011111100011100100111… |
… | …0101010001111010111011 |
3 | 1201111111211101220122001221 |
4 | 2333013021311101322323 |
5 | 3210133042402230243 |
6 | 43533132521252511 |
7 | 2523556330260232 |
oct | 277071165217273 |
9 | 51444741818057 |
10 | 13133101211323 |
11 | 4203798288895 |
12 | 1581349034137 |
13 | 7435a51c0422 |
14 | 335907321b19 |
15 | 17b94e8d2bed |
hex | bf1c9d51ebb |
13133101211323 has 2 divisors, whose sum is σ = 13133101211324. Its totient is φ = 13133101211322.
The previous prime is 13133101211231. The next prime is 13133101211327. The reversal of 13133101211323 is 32311210133131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13133101211323 - 221 = 13133099114171 is a prime.
It is not a weakly prime, because it can be changed into another prime (13133101211327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566550605661 + 6566550605662.
It is an arithmetic number, because the mean of its divisors is an integer number (6566550605662).
Almost surely, 213133101211323 is an apocalyptic number.
13133101211323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133101211323 is an equidigital number, since it uses as much as digits as its factorization.
13133101211323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 13133101211323 its reverse (32311210133131), we get a palindrome (45444311344454).
The spelling of 13133101211323 in words is "thirteen trillion, one hundred thirty-three billion, one hundred one million, two hundred eleven thousand, three hundred twenty-three".
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