Base | Representation |
---|---|
bin | 1011111100011100101100… |
… | …1100111110011001100111 |
3 | 1201111111220000011120122212 |
4 | 2333013023030332121213 |
5 | 3210133114243400124 |
6 | 43533135102114035 |
7 | 2523560026544564 |
oct | 277071314763147 |
9 | 51444800146585 |
10 | 13133124200039 |
11 | 42037aa25a628 |
12 | 158135487b91b |
13 | 7435a9bac00c |
14 | 33590a3c786b |
15 | 17b95192440e |
hex | bf1cb33e667 |
13133124200039 has 2 divisors, whose sum is σ = 13133124200040. Its totient is φ = 13133124200038.
The previous prime is 13133124199981. The next prime is 13133124200087. The reversal of 13133124200039 is 93000242133131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13133124200039 - 216 = 13133124134503 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13133124199978 and 13133124200014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13133124200639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566562100019 + 6566562100020.
It is an arithmetic number, because the mean of its divisors is an integer number (6566562100020).
Almost surely, 213133124200039 is an apocalyptic number.
13133124200039 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133124200039 is an equidigital number, since it uses as much as digits as its factorization.
13133124200039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 32.
The spelling of 13133124200039 in words is "thirteen trillion, one hundred thirty-three billion, one hundred twenty-four million, two hundred thousand, thirty-nine".
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