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131332220231 is a prime number
BaseRepresentation
bin111101001010000000…
…0101010010101000111
3110112222202202001012212
41322110000222111013
54122432022021411
6140155545134035
712326351311232
oct1722400522507
9415882661185
10131332220231
1150774683993
1221552a8a31b
13c4ccbb1224
1464dc3b6419
153639cba68b
hex1e9402a547

131332220231 has 2 divisors, whose sum is σ = 131332220232. Its totient is φ = 131332220230.

The previous prime is 131332220183. The next prime is 131332220233. The reversal of 131332220231 is 132022233131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131332220231 is a prime.

It is a super-2 number, since 2×1313322202312 (a number of 23 digits) contains 22 as substring.

Together with 131332220233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131332220197 and 131332220206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131332220233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65666110115 + 65666110116.

It is an arithmetic number, because the mean of its divisors is an integer number (65666110116).

Almost surely, 2131332220231 is an apocalyptic number.

131332220231 is a deficient number, since it is larger than the sum of its proper divisors (1).

131332220231 is an equidigital number, since it uses as much as digits as its factorization.

131332220231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 131332220231 its reverse (132022233131), we get a palindrome (263354453362).

The spelling of 131332220231 in words is "one hundred thirty-one billion, three hundred thirty-two million, two hundred twenty thousand, two hundred thirty-one".