Base | Representation |
---|---|
bin | 10011000111001000100… |
… | …100011001110000100011 |
3 | 11122112221020010011220121 |
4 | 103013020210121300203 |
5 | 133004144440324141 |
6 | 2443200244021111 |
7 | 163612353621613 |
oct | 23071044316043 |
9 | 4575836104817 |
10 | 1313330011171 |
11 | 466a86609952 |
12 | 192647691797 |
13 | 96b00974009 |
14 | 477cba9aa43 |
15 | 242693131d1 |
hex | 131c8919c23 |
1313330011171 has 2 divisors, whose sum is σ = 1313330011172. Its totient is φ = 1313330011170.
The previous prime is 1313330011117. The next prime is 1313330011219. The reversal of 1313330011171 is 1711100333131.
It is a happy number.
Together with previous prime (1313330011117) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1313330011171 - 217 = 1313329880099 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313330011271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656665005585 + 656665005586.
It is an arithmetic number, because the mean of its divisors is an integer number (656665005586).
Almost surely, 21313330011171 is an apocalyptic number.
1313330011171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313330011171 is an equidigital number, since it uses as much as digits as its factorization.
1313330011171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 567, while the sum is 25.
The spelling of 1313330011171 in words is "one trillion, three hundred thirteen billion, three hundred thirty million, eleven thousand, one hundred seventy-one".
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