Base | Representation |
---|---|
bin | 1011111100011101011001… |
… | …0001100010011111000101 |
3 | 1201111112100221200102221101 |
4 | 2333013112101202133011 |
5 | 3210134004321231142 |
6 | 43533205335220101 |
7 | 2523564443423446 |
oct | 277072621423705 |
9 | 51445327612841 |
10 | 13133309945797 |
11 | 4203895097118 |
12 | 15813a6b17631 |
13 | 743609515252 |
14 | 335926d392cd |
15 | 17b962db50b7 |
hex | bf1d64627c5 |
13133309945797 has 2 divisors, whose sum is σ = 13133309945798. Its totient is φ = 13133309945796.
The previous prime is 13133309945761. The next prime is 13133309945813. The reversal of 13133309945797 is 79754990333131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11716100648641 + 1417209297156 = 3422879^2 + 1190466^2 .
It is a cyclic number.
It is not a de Polignac number, because 13133309945797 - 227 = 13133175728069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13133309945897) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566654972898 + 6566654972899.
It is an arithmetic number, because the mean of its divisors is an integer number (6566654972899).
Almost surely, 213133309945797 is an apocalyptic number.
It is an amenable number.
13133309945797 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133309945797 is an equidigital number, since it uses as much as digits as its factorization.
13133309945797 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57868020, while the sum is 64.
The spelling of 13133309945797 in words is "thirteen trillion, one hundred thirty-three billion, three hundred nine million, nine hundred forty-five thousand, seven hundred ninety-seven".
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