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131333101311110 = 2513133310131111
BaseRepresentation
bin11101110111001001011110…
…110110011101010010000110
3122020000022200122022120102112
4131313021132312131102012
5114203230142413423420
61143153332133341022
736443334452660306
oct3567113666352206
9566008618276375
10131333101311110
1138935067930386
1212891299a97772
13583887340b43a
1424607ada0b606
15102b41e4ee8c5
hex77725ed9d486

131333101311110 has 8 divisors (see below), whose sum is σ = 236399582360016. Its totient is φ = 52533240524440.

The previous prime is 131333101311103. The next prime is 131333101311241. The reversal of 131333101311110 is 11113101333131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6566655065546 + ... + 6566655065565.

It is an arithmetic number, because the mean of its divisors is an integer number (29549947795002).

Almost surely, 2131333101311110 is an apocalyptic number.

131333101311110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131333101311110 is a deficient number, since it is larger than the sum of its proper divisors (105066481048906).

131333101311110 is a wasteful number, since it uses less digits than its factorization.

131333101311110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13133310131118.

The product of its (nonzero) digits is 243, while the sum is 23.

Adding to 131333101311110 its reverse (11113101333131), we get a palindrome (142446202644241).

The spelling of 131333101311110 in words is "one hundred thirty-one trillion, three hundred thirty-three billion, one hundred one million, three hundred eleven thousand, one hundred ten".

Divisors: 1 2 5 10 13133310131111 26266620262222 65666550655555 131333101311110