Base | Representation |
---|---|
bin | 10011000111001000110… |
… | …000111111001010010111 |
3 | 11122112221110022210012021 |
4 | 103013020300333022113 |
5 | 133004201311410403 |
6 | 2443200442434011 |
7 | 163612423641523 |
oct | 23071060771227 |
9 | 4575843283167 |
10 | 1313333310103 |
11 | 466a88462441 |
12 | 192648802907 |
13 | 96b0155a749 |
14 | 477cc2b8d83 |
15 | 242697658bd |
hex | 131c8c3f297 |
1313333310103 has 2 divisors, whose sum is σ = 1313333310104. Its totient is φ = 1313333310102.
The previous prime is 1313333310089. The next prime is 1313333310137. The reversal of 1313333310103 is 3010133333131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1313333310103 - 233 = 1304743375511 is a prime.
It is a super-2 number, since 2×13133333101032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313333310173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656666655051 + 656666655052.
It is an arithmetic number, because the mean of its divisors is an integer number (656666655052).
Almost surely, 21313333310103 is an apocalyptic number.
1313333310103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313333310103 is an equidigital number, since it uses as much as digits as its factorization.
1313333310103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2187, while the sum is 25.
Adding to 1313333310103 its reverse (3010133333131), we get a palindrome (4323466643234).
The spelling of 1313333310103 in words is "one trillion, three hundred thirteen billion, three hundred thirty-three million, three hundred ten thousand, one hundred three".
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