1313343131 has 2 divisors, whose sum is σ = 1313343132. Its totient is φ = 1313343130.

The previous prime is 1313343121. The next prime is 1313343133. The reversal of 1313343131 is 1313433131.

It is a strong prime.

It is an emirp because it is prime and its reverse (1313433131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1313343131 - 2¹⁸ = 1313080987 is a prime.

It is a super-2 number, since 2×1313343131² = 3449740359489766322, which contains 22 as substring.

Together with 1313343133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1313343097 and 1313343106.

It is not a weakly prime, because it can be changed into another prime (1313343133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656671565 + 656671566.

It is an arithmetic number, because the mean of its divisors is an integer number (656671566).

Almost surely, 2^1313343131 is an apocalyptic number.

1313343131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313343131 is an equidigital number, since it uses as much as digits as its factorization.

1313343131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 972, while the sum is 23.

The square root of 1313343131 is about 36240.0763106261. The cubic root of 1313343131 is about 1095.1141797633.

Adding to 1313343131 its reverse (1313433131), we get a palindrome (2626776262).

Subtracting 1313343131 from its reverse (1313433131), we obtain a square (90000 = 300²).

The spelling of 1313343131 in words is "one billion, three hundred thirteen million, three hundred forty-three thousand, one hundred thirty-one".