Base | Representation |
---|---|
bin | 11101110111001111111010… |
… | …110100100111011001010000 |
3 | 122020000222112022221211201001 |
4 | 131313033322310213121100 |
5 | 114203333321314304412 |
6 | 1143200434035551344 |
7 | 36444000650501062 |
oct | 3567177264473120 |
9 | 566028468854631 |
10 | 131340013041232 |
11 | 38937a94375536 |
12 | 128926a875b554 |
13 | 5839405349a88 |
14 | 2460c6794b732 |
15 | 102b6c61ce957 |
hex | 7773fad27650 |
131340013041232 has 40 divisors (see below), whose sum is σ = 267953464121760. Its totient is φ = 62193027818880.
The previous prime is 131340013041203. The next prime is 131340013041299. The reversal of 131340013041232 is 232140310043131.
It is a self number, because there is not a number n which added to its sum of digits gives 131340013041232.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70828183 + ... + 72658870.
It is an arithmetic number, because the mean of its divisors is an integer number (6698836603044).
Almost surely, 2131340013041232 is an apocalyptic number.
It is an amenable number.
131340013041232 is an abundant number, since it is smaller than the sum of its proper divisors (136613451080528).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131340013041232 is a wasteful number, since it uses less digits than its factorization.
131340013041232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143490091 (or 143490085 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 131340013041232 its reverse (232140310043131), we get a palindrome (363480323084363).
The spelling of 131340013041232 in words is "one hundred thirty-one trillion, three hundred forty billion, thirteen million, forty-one thousand, two hundred thirty-two".
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