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1313401120063 is a prime number
BaseRepresentation
bin10011000111001100110…
…011101010010100111111
311122120010011220212222021
4103013030303222110333
5133004321141320223
62443211304101011
7163614206214304
oct23071463522477
94576104825867
101313401120063
1146701276802a
12192667464767
1396b12610496
14477d72cb0ab
15242706ac65d
hex131cccea53f

1313401120063 has 2 divisors, whose sum is σ = 1313401120064. Its totient is φ = 1313401120062.

The previous prime is 1313401120043. The next prime is 1313401120067. The reversal of 1313401120063 is 3600211043131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1313401120063 - 29 = 1313401119551 is a prime.

It is a super-2 number, since 2×13134011200632 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313401120067) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656700560031 + 656700560032.

It is an arithmetic number, because the mean of its divisors is an integer number (656700560032).

Almost surely, 21313401120063 is an apocalyptic number.

1313401120063 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313401120063 is an equidigital number, since it uses as much as digits as its factorization.

1313401120063 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1313401120063 its reverse (3600211043131), we get a palindrome (4913612163194).

The spelling of 1313401120063 in words is "one trillion, three hundred thirteen billion, four hundred one million, one hundred twenty thousand, sixty-three".