13134030433 has 2 divisors, whose sum is σ = 13134030434. Its totient is φ = 13134030432.

The previous prime is 13134030409. The next prime is 13134030439. The reversal of 13134030433 is 33403043131.

It is a happy number.

13134030433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7026295329 + 6107735104 = 83823^2 + 78152^2 .

It is a cyclic number.

It is not a de Polignac number, because 13134030433 - 2⁹ = 13134029921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13134030398 and 13134030407.

It is not a weakly prime, because it can be changed into another prime (13134030439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567015216 + 6567015217.

It is an arithmetic number, because the mean of its divisors is an integer number (6567015217).

Almost surely, 2^13134030433 is an apocalyptic number.

It is an amenable number.

13134030433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13134030433 is an equidigital number, since it uses as much as digits as its factorization.

13134030433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 13134030433 its reverse (33403043131), we get a palindrome (46537073564).

The spelling of 13134030433 in words is "thirteen billion, one hundred thirty-four million, thirty thousand, four hundred thirty-three".