Base | Representation |
---|---|
bin | 10011000111001101011… |
… | …111010011010011101011 |
3 | 11122120010222110002202121 |
4 | 103013031133103103223 |
5 | 133004332103410412 |
6 | 2443212353212111 |
7 | 163614405362224 |
oct | 23071537232353 |
9 | 4576128402677 |
10 | 1313412560107 |
11 | 46701917110a |
12 | 19266b261037 |
13 | 96b14ab763b |
14 | 477d8a2824b |
15 | 242716bc107 |
hex | 131cd7d34eb |
1313412560107 has 2 divisors, whose sum is σ = 1313412560108. Its totient is φ = 1313412560106.
The previous prime is 1313412560011. The next prime is 1313412560143. The reversal of 1313412560107 is 7010652143131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313412560107 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313412560177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656706280053 + 656706280054.
It is an arithmetic number, because the mean of its divisors is an integer number (656706280054).
Almost surely, 21313412560107 is an apocalyptic number.
1313412560107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313412560107 is an equidigital number, since it uses as much as digits as its factorization.
1313412560107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 34.
The spelling of 1313412560107 in words is "one trillion, three hundred thirteen billion, four hundred twelve million, five hundred sixty thousand, one hundred seven".
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