1313412560143 has 2 divisors, whose sum is σ = 1313412560144. Its totient is φ = 1313412560142.

The previous prime is 1313412560107. The next prime is 1313412560177. The reversal of 1313412560143 is 3410652143131.

It is an a-pointer prime, because the next prime (1313412560177) can be obtained adding 1313412560143 to its sum of digits (34).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1313412560143 - 2¹⁷ = 1313412429071 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1313412560099 and 1313412560108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313412563143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656706280071 + 656706280072.

It is an arithmetic number, because the mean of its divisors is an integer number (656706280072).

Almost surely, 2^{1313412560143} is an apocalyptic number.

1313412560143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313412560143 is an equidigital number, since it uses as much as digits as its factorization.

1313412560143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 34.

The spelling of 1313412560143 in words is "one trillion, three hundred thirteen billion, four hundred twelve million, five hundred sixty thousand, one hundred forty-three".