Base | Representation |
---|---|
bin | 11101110111010010001011… |
… | …011111011111011101000000 |
3 | 122020001012210111002021121020 |
4 | 131313102023133133131000 |
5 | 114203403304142400000 |
6 | 1143201514542225440 |
7 | 36444115052140521 |
oct | 3567221337373500 |
9 | 566035714067536 |
10 | 131342440200000 |
11 | 3893901a447877 |
12 | 12893065585280 |
13 | 58397011543b3 |
14 | 246101803a848 |
15 | 102b7b931cba0 |
hex | 77748b7df740 |
131342440200000 has 336 divisors, whose sum is σ = 438660753164928. Its totient is φ = 34677856000000.
The previous prime is 131342440199969. The next prime is 131342440200007. The reversal of 131342440200000 is 2044243131.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131342440200007) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 59516317 + ... + 61683683.
It is an arithmetic number, because the mean of its divisors is an integer number (1305537955848).
Almost surely, 2131342440200000 is an apocalyptic number.
131342440200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131342440200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (219330376582464).
131342440200000 is an abundant number, since it is smaller than the sum of its proper divisors (307318312964928).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131342440200000 is an equidigital number, since it uses as much as digits as its factorization.
131342440200000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2167508 (or 2167478 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 131342440200000 its reverse (2044243131), we get a palindrome (131344484443131).
The spelling of 131342440200000 in words is "one hundred thirty-one trillion, three hundred forty-two billion, four hundred forty million, two hundred thousand".
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