Base | Representation |
---|---|
bin | 11101110111010010001011… |
… | …100010111110011001111010 |
3 | 122020001012210112210200021211 |
4 | 131313102023202332121322 |
5 | 114203403304411110320 |
6 | 1143201515013553334 |
7 | 36444115062663115 |
oct | 3567221342763172 |
9 | 566035715720254 |
10 | 131342441113210 |
11 | 3893901aa10998 |
12 | 1289306594584a |
13 | 58397013b3c62 |
14 | 24610181d757c |
15 | 102b7b944d55a |
hex | 77748b8be67a |
131342441113210 has 32 divisors (see below), whose sum is σ = 250148788925760. Its totient is φ = 49513987058688.
The previous prime is 131342441113207. The next prime is 131342441113253. The reversal of 131342441113210 is 12311144243131.
131342441113210 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1790833812 + ... + 1790907151.
It is an arithmetic number, because the mean of its divisors is an integer number (7817149653930).
Almost surely, 2131342441113210 is an apocalyptic number.
131342441113210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131342441113210 is a deficient number, since it is larger than the sum of its proper divisors (118806347812550).
131342441113210 is a wasteful number, since it uses less digits than its factorization.
131342441113210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3581741182.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 131342441113210 its reverse (12311144243131), we get a palindrome (143653585356341).
The spelling of 131342441113210 in words is "one hundred thirty-one trillion, three hundred forty-two billion, four hundred forty-one million, one hundred thirteen thousand, two hundred ten".
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