1313426021540 has 24 divisors (see below), whose sum is σ = 2847168667392. Its totient is φ = 508422975840.

The previous prime is 1313426021521. The next prime is 1313426021561. The reversal of 1313426021540 is 451206243131.

It is a junction number, because it is equal to n+sod(n) for n = 1313426021497 and 1313426021506.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1059213914 + ... + 1059215153.

It is an arithmetic number, because the mean of its divisors is an integer number (118632027808).

Almost surely, 2^{1313426021540} is an apocalyptic number.

1313426021540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1313426021540 is an abundant number, since it is smaller than the sum of its proper divisors (1533742645852).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1313426021540 is a wasteful number, since it uses less digits than its factorization.

1313426021540 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2118429107 (or 2118429105 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 32.

The spelling of 1313426021540 in words is "one trillion, three hundred thirteen billion, four hundred twenty-six million, twenty-one thousand, five hundred forty".