Base | Representation |
---|---|
bin | 11101110111010010111010… |
… | …100101111010100011001101 |
3 | 122020001021211120000021001120 |
4 | 131313102322211322203031 |
5 | 114203411413441204010 |
6 | 1143202125211231153 |
7 | 36444143455632522 |
oct | 3567227245724315 |
9 | 566037746007046 |
10 | 131343230413005 |
11 | 38939395503576 |
12 | 128932461484b9 |
13 | 58397c8a8b660 |
14 | 2461090d79149 |
15 | 102b8138aee70 |
hex | 7774ba97a8cd |
131343230413005 has 64 divisors (see below), whose sum is σ = 231993383973120. Its totient is φ = 63044140916736.
The previous prime is 131343230412983. The next prime is 131343230413033. The reversal of 131343230413005 is 500314032343131.
It is a happy number.
It is not a de Polignac number, because 131343230413005 - 215 = 131343230380237 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 9390660 + ... + 18731549.
It is an arithmetic number, because the mean of its divisors is an integer number (3624896624580).
Almost surely, 2131343230413005 is an apocalyptic number.
131343230413005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
131343230413005 is a deficient number, since it is larger than the sum of its proper divisors (100650153560115).
131343230413005 is a wasteful number, since it uses less digits than its factorization.
131343230413005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28122830.
The product of its (nonzero) digits is 38880, while the sum is 33.
Adding to 131343230413005 its reverse (500314032343131), we get a palindrome (631657262756136).
The spelling of 131343230413005 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred thirty million, four hundred thirteen thousand, five".
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