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1313433131010 = 23571113372834177
BaseRepresentation
bin10011000111001110101…
…101110001100000000010
311122120012102011012201220
4103013032231301200002
5133004402340143020
62443214410135510
7163615045256550
oct23071655614002
94576172135656
101313433131010
11467029841360
12192676121596
1396b1913a880
14477db660bd0
15242733d2240
hex131ceb71802

1313433131010 has 512 divisors, whose sum is σ = 4363170029568. Its totient is φ = 244193771520.

The previous prime is 1313433130991. The next prime is 1313433131027. The reversal of 1313433131010 is 101313343131.

It is an unprimeable number.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 314442042 + ... + 314446218.

It is an arithmetic number, because the mean of its divisors is an integer number (8521816464).

Almost surely, 21313433131010 is an apocalyptic number.

1313433131010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 1313433131010, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2181585014784).

1313433131010 is an abundant number, since it is smaller than the sum of its proper divisors (3049736898558).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1313433131010 is a wasteful number, since it uses less digits than its factorization.

1313433131010 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4538.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 1313433131010 its reverse (101313343131), we get a palindrome (1414746474141).

The spelling of 1313433131010 in words is "one trillion, three hundred thirteen billion, four hundred thirty-three million, one hundred thirty-one thousand, ten".