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13134342031 is a prime number
BaseRepresentation
bin11000011101101111…
…00010011110001111
31020220100120201002021
430032313202132033
5203344342421111
610011150311011
7643324031236
oct141667423617
936810521067
1013134342031
11562aaa2628
1226667b8467
13131417a925
148c8539b1d
1551d13bd71
hex30ede278f

13134342031 has 2 divisors, whose sum is σ = 13134342032. Its totient is φ = 13134342030.

The previous prime is 13134342019. The next prime is 13134342037. The reversal of 13134342031 is 13024343131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13134342031 - 27 = 13134341903 is a prime.

It is a super-2 number, since 2×131343420312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13134341987 and 13134342005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13134342037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567171015 + 6567171016.

It is an arithmetic number, because the mean of its divisors is an integer number (6567171016).

Almost surely, 213134342031 is an apocalyptic number.

13134342031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13134342031 is an equidigital number, since it uses as much as digits as its factorization.

13134342031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13134342031 its reverse (13024343131), we get a palindrome (26158685162).

The spelling of 13134342031 in words is "thirteen billion, one hundred thirty-four million, three hundred forty-two thousand, thirty-one".