Base | Representation |
---|---|
bin | 11101110111010011111101… |
… | …011010100100011010001000 |
3 | 122020001101201200120000000222 |
4 | 131313103331122210122020 |
5 | 114203421212441342300 |
6 | 1143202432340245212 |
7 | 36444213321053351 |
oct | 3567237532443210 |
9 | 566041650500028 |
10 | 131344351512200 |
11 | 38939910319a32 |
12 | 128934b96a0808 |
13 | 5839947118b68 |
14 | 2461159c0ad28 |
15 | 102b87c012785 |
hex | 7774fd6a4688 |
131344351512200 has 24 divisors (see below), whose sum is σ = 305375617266330. Its totient is φ = 52537740604800.
The previous prime is 131344351512191. The next prime is 131344351512217. The reversal of 131344351512200 is 2215153443131.
It can be written as a sum of positive squares in 3 ways, for example, as 115888712886244 + 15455638625956 = 10765162^2 + 3931366^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 328360878581 + ... + 328360878980.
Almost surely, 2131344351512200 is an apocalyptic number.
131344351512200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131344351512200 is an abundant number, since it is smaller than the sum of its proper divisors (174031265754130).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131344351512200 is a wasteful number, since it uses less digits than its factorization.
131344351512200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 656721757577 (or 656721757568 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 35.
The spelling of 131344351512200 in words is "one hundred thirty-one trillion, three hundred forty-four billion, three hundred fifty-one million, five hundred twelve thousand, two hundred".
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