Base | Representation |
---|---|
bin | 1011111100100001101000… |
… | …1110111110000100101010 |
3 | 1201111122022102010110002112 |
4 | 2333020122032332010222 |
5 | 3210143323212414200 |
6 | 43533514425202322 |
7 | 2523634626653414 |
oct | 277103216760452 |
9 | 51448272113075 |
10 | 13134450123050 |
11 | 420431a753173 |
12 | 15816649303a2 |
13 | 74375b7c2349 |
14 | 3359d45359b4 |
15 | 17b9cd035535 |
hex | bf21a3be12a |
13134450123050 has 48 divisors (see below), whose sum is σ = 24570029417472. Its totient is φ = 5223717441600.
The previous prime is 13134450123037. The next prime is 13134450123073. The reversal of 13134450123050 is 5032105443131.
It is a junction number, because it is equal to n+sod(n) for n = 13134450122998 and 13134450123016.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14766455 + ... + 15630645.
It is an arithmetic number, because the mean of its divisors is an integer number (511875612864).
Almost surely, 213134450123050 is an apocalyptic number.
13134450123050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13134450123050 is a deficient number, since it is larger than the sum of its proper divisors (11435579294422).
13134450123050 is a wasteful number, since it uses less digits than its factorization.
13134450123050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 865943 (or 865938 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 13134450123050 its reverse (5032105443131), we get a palindrome (18166555566181).
The spelling of 13134450123050 in words is "thirteen trillion, one hundred thirty-four billion, four hundred fifty million, one hundred twenty-three thousand, fifty".
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