Base | Representation |
---|---|
bin | 11101110111010100111100… |
… | …011010110111011100110111 |
3 | 122020001111110100120022220011 |
4 | 131313110330122313130313 |
5 | 114203430344042223212 |
6 | 1143203125300321051 |
7 | 36444251444553256 |
oct | 3567247432673467 |
9 | 566044410508804 |
10 | 131345408554807 |
11 | 3893a302a63767 |
12 | 128937536a3187 |
13 | 5839a85108b65 |
14 | 246121a36679d |
15 | 102b8dec104a7 |
hex | 77753c6b7737 |
131345408554807 has 2 divisors, whose sum is σ = 131345408554808. Its totient is φ = 131345408554806.
The previous prime is 131345408554777. The next prime is 131345408554897. The reversal of 131345408554807 is 708455804543131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131345408554807 - 239 = 130795652740919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131345408554897) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65672704277403 + 65672704277404.
It is an arithmetic number, because the mean of its divisors is an integer number (65672704277404).
Almost surely, 2131345408554807 is an apocalyptic number.
131345408554807 is a deficient number, since it is larger than the sum of its proper divisors (1).
131345408554807 is an equidigital number, since it uses as much as digits as its factorization.
131345408554807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32256000, while the sum is 58.
The spelling of 131345408554807 in words is "one hundred thirty-one trillion, three hundred forty-five billion, four hundred eight million, five hundred fifty-four thousand, eight hundred seven".
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