131345425332137 has 2 divisors, whose sum is σ = 131345425332138. Its totient is φ = 131345425332136.

The previous prime is 131345425331999. The next prime is 131345425332139. The reversal of 131345425332137 is 731233524543131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127932024975616 + 3413400356521 = 11310704^2 + 1847539^2 .

It is an emirp because it is prime and its reverse (731233524543131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131345425332137 - 2¹² = 131345425328041 is a prime.

Together with 131345425332139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131345425332091 and 131345425332100.

It is not a weakly prime, because it can be changed into another prime (131345425332139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65672712666068 + 65672712666069.

It is an arithmetic number, because the mean of its divisors is an integer number (65672712666069).

Almost surely, 2^{131345425332137} is an apocalyptic number.

It is an amenable number.

131345425332137 is a deficient number, since it is larger than the sum of its proper divisors (1).

131345425332137 is an equidigital number, since it uses as much as digits as its factorization.

131345425332137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2721600, while the sum is 47.

Adding to 131345425332137 its reverse (731233524543131), we get a palindrome (862578949875268).

The spelling of 131345425332137 in words is "one hundred thirty-one trillion, three hundred forty-five billion, four hundred twenty-five million, three hundred thirty-two thousand, one hundred thirty-seven".