13134750229451 has 2 divisors, whose sum is σ = 13134750229452. Its totient is φ = 13134750229450.

The previous prime is 13134750229399. The next prime is 13134750229453. The reversal of 13134750229451 is 15492205743131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13134750229451 - 2¹⁰ = 13134750228427 is a prime.

It is a super-2 number, since 2×13134750229451² (a number of 27 digits) contains 22 as substring.

Together with 13134750229453, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13134750229396 and 13134750229405.

It is not a weakly prime, because it can be changed into another prime (13134750229453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567375114725 + 6567375114726.

It is an arithmetic number, because the mean of its divisors is an integer number (6567375114726).

Almost surely, 2^{13134750229451} is an apocalyptic number.

13134750229451 is a deficient number, since it is larger than the sum of its proper divisors (1).

13134750229451 is an equidigital number, since it uses as much as digits as its factorization.

13134750229451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 907200, while the sum is 47.

The spelling of 13134750229451 in words is "thirteen trillion, one hundred thirty-four billion, seven hundred fifty million, two hundred twenty-nine thousand, four hundred fifty-one".