Base | Representation |
---|---|
bin | 1011111100100100100111… |
… | …1010011101000101011111 |
3 | 1201111201101011100000112022 |
4 | 2333021021322131011133 |
5 | 3210201443003121143 |
6 | 43534130042330355 |
7 | 2523663512151203 |
oct | 277111172350537 |
9 | 51451334300468 |
10 | 13135250051423 |
11 | 42046a02451a5 |
12 | 15818487b99bb |
13 | 74385844b746 |
14 | 335a6c882b03 |
15 | 17ba28396268 |
hex | bf249e9d15f |
13135250051423 has 2 divisors, whose sum is σ = 13135250051424. Its totient is φ = 13135250051422.
The previous prime is 13135250051401. The next prime is 13135250051449. The reversal of 13135250051423 is 32415005253131.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (32415005253131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13135250051423 - 28 = 13135250051167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13135250051453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567625025711 + 6567625025712.
It is an arithmetic number, because the mean of its divisors is an integer number (6567625025712).
Almost surely, 213135250051423 is an apocalyptic number.
13135250051423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13135250051423 is an equidigital number, since it uses as much as digits as its factorization.
13135250051423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 35.
The spelling of 13135250051423 in words is "thirteen trillion, one hundred thirty-five billion, two hundred fifty million, fifty-one thousand, four hundred twenty-three".
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