Base | Representation |
---|---|
bin | 1011111100100101000000… |
… | …0111110100010100011010 |
3 | 1201111201122102100012212120 |
4 | 2333021100013310110122 |
5 | 3210202201134432004 |
6 | 43534144243122110 |
7 | 2523666215435136 |
oct | 277112007642432 |
9 | 51451572305776 |
10 | 13135354217754 |
11 | 420474402197a |
12 | 1581877673336 |
13 | 743873bc0722 |
14 | 335a7c63a3c6 |
15 | 17ba325c03d9 |
hex | bf2501f451a |
13135354217754 has 32 divisors (see below), whose sum is σ = 27844809734016. Its totient is φ = 4116633884160.
The previous prime is 13135354217719. The next prime is 13135354217801. The reversal of 13135354217754 is 45771245353131.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a junction number, because it is equal to n+sod(n) for n = 13135354217697 and 13135354217706.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 66487707 + ... + 66684974.
It is an arithmetic number, because the mean of its divisors is an integer number (870150304188).
Almost surely, 213135354217754 is an apocalyptic number.
13135354217754 is an abundant number, since it is smaller than the sum of its proper divisors (14709455516262).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13135354217754 is a wasteful number, since it uses less digits than its factorization.
13135354217754 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 133173670.
The product of its digits is 5292000, while the sum is 51.
The spelling of 13135354217754 in words is "thirteen trillion, one hundred thirty-five billion, three hundred fifty-four million, two hundred seventeen thousand, seven hundred fifty-four".
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