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1313563453450 = 25226271269069
BaseRepresentation
bin10011000111010110011…
…110111010100000001010
311122120112111101021111221
4103013112132322200022
5133010134221002300
62443235343312254
7163621220062423
oct23072636724012
94576474337457
101313563453450
11467096363556
121926b18ab68a
1396b3a13a041
1447810aa664a
152427ea7631a
hex131d67ba80a

1313563453450 has 12 divisors (see below), whose sum is σ = 2443228023510. Its totient is φ = 525425381360.

The previous prime is 1313563453439. The next prime is 1313563453453. The reversal of 1313563453450 is 543543653131.

It can be written as a sum of positive squares in 3 ways, for example, as 775560274281 + 538003179169 = 880659^2 + 733487^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1313563453397 and 1313563453406.

It is not an unprimeable number, because it can be changed into a prime (1313563453453) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 13135634485 + ... + 13135634584.

Almost surely, 21313563453450 is an apocalyptic number.

1313563453450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1313563453450 is a deficient number, since it is larger than the sum of its proper divisors (1129664570060).

1313563453450 is a wasteful number, since it uses less digits than its factorization.

1313563453450 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26271269081 (or 26271269076 counting only the distinct ones).

The product of its (nonzero) digits is 972000, while the sum is 43.

The spelling of 1313563453450 in words is "one trillion, three hundred thirteen billion, five hundred sixty-three million, four hundred fifty-three thousand, four hundred fifty".

Divisors: 1 2 5 10 25 50 26271269069 52542538138 131356345345 262712690690 656781726725 1313563453450