Base | Representation |
---|---|
bin | 1011111100101000110010… |
… | …1000011101011001101101 |
3 | 1201111211021011121012112101 |
4 | 2333022030220131121231 |
5 | 3210211241032020342 |
6 | 43534433110135101 |
7 | 2524033323422242 |
oct | 277121450353155 |
9 | 51454234535471 |
10 | 13136369407597 |
11 | 4205115080047 |
12 | 1581abb651491 |
13 | 7439a6318787 |
14 | 335b373bd5c9 |
15 | 17ba917a23b7 |
hex | bf28ca1d66d |
13136369407597 has 2 divisors, whose sum is σ = 13136369407598. Its totient is φ = 13136369407596.
The previous prime is 13136369407591. The next prime is 13136369407631. The reversal of 13136369407597 is 79570496363131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11801018138121 + 1335351269476 = 3435261^2 + 1155574^2 .
It is a cyclic number.
It is not a de Polignac number, because 13136369407597 - 23 = 13136369407589 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13136369407591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6568184703798 + 6568184703799.
It is an arithmetic number, because the mean of its divisors is an integer number (6568184703799).
Almost surely, 213136369407597 is an apocalyptic number.
It is an amenable number.
13136369407597 is a deficient number, since it is larger than the sum of its proper divisors (1).
13136369407597 is an equidigital number, since it uses as much as digits as its factorization.
13136369407597 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77157360, while the sum is 64.
The spelling of 13136369407597 in words is "thirteen trillion, one hundred thirty-six billion, three hundred sixty-nine million, four hundred seven thousand, five hundred ninety-seven".
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