Base | Representation |
---|---|
bin | 111101001011010100… |
… | …1010111010100011101 |
3 | 110120002211221212210012 |
4 | 1322112221113110131 |
5 | 4123024332212301 |
6 | 140204205053005 |
7 | 12330426232445 |
oct | 1722651272435 |
9 | 416084855705 |
10 | 131376444701 |
11 | 5079763a437 |
12 | 21565857165 |
13 | c5090c6858 |
14 | 6504209125 |
15 | 363db03ebb |
hex | 1e96a5751d |
131376444701 has 2 divisors, whose sum is σ = 131376444702. Its totient is φ = 131376444700.
The previous prime is 131376444671. The next prime is 131376444721. The reversal of 131376444701 is 107444673131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 94522428025 + 36854016676 = 307445^2 + 191974^2 .
It is an emirp because it is prime and its reverse (107444673131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131376444701 - 218 = 131376182557 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131376444721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65688222350 + 65688222351.
It is an arithmetic number, because the mean of its divisors is an integer number (65688222351).
Almost surely, 2131376444701 is an apocalyptic number.
It is an amenable number.
131376444701 is a deficient number, since it is larger than the sum of its proper divisors (1).
131376444701 is an equidigital number, since it uses as much as digits as its factorization.
131376444701 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 169344, while the sum is 41.
The spelling of 131376444701 in words is "one hundred thirty-one billion, three hundred seventy-six million, four hundred forty-four thousand, seven hundred one".
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