Base | Representation |
---|---|
bin | 111101001011010100… |
… | …1011100000010111001 |
3 | 110120002211222212100002 |
4 | 1322112221130002321 |
5 | 4123024333322212 |
6 | 140204205322345 |
7 | 12330426343046 |
oct | 1722651340271 |
9 | 416084885302 |
10 | 131376464057 |
11 | 50797652a33 |
12 | 215658663b5 |
13 | c5091025c7 |
14 | 65042121cd |
15 | 363db09ac2 |
hex | 1e96a5c0b9 |
131376464057 has 2 divisors, whose sum is σ = 131376464058. Its totient is φ = 131376464056.
The previous prime is 131376464039. The next prime is 131376464059. The reversal of 131376464057 is 750464673131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 80645208361 + 50731255696 = 283981^2 + 225236^2 .
It is a cyclic number.
It is not a de Polignac number, because 131376464057 - 210 = 131376463033 is a prime.
Together with 131376464059, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131376464059) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65688232028 + 65688232029.
It is an arithmetic number, because the mean of its divisors is an integer number (65688232029).
Almost surely, 2131376464057 is an apocalyptic number.
It is an amenable number.
131376464057 is a deficient number, since it is larger than the sum of its proper divisors (1).
131376464057 is an equidigital number, since it uses as much as digits as its factorization.
131376464057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1270080, while the sum is 47.
The spelling of 131376464057 in words is "one hundred thirty-one billion, three hundred seventy-six million, four hundred sixty-four thousand, fifty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •