13138825145077 has 2 divisors, whose sum is σ = 13138825145078. Its totient is φ = 13138825145076.

The previous prime is 13138825145059. The next prime is 13138825145183. The reversal of 13138825145077 is 77054152883131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6571501488036 + 6567323657041 = 2563494^2 + 2562679^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13138825145077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13138825143077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6569412572538 + 6569412572539.

It is an arithmetic number, because the mean of its divisors is an integer number (6569412572539).

Almost surely, 2^{13138825145077} is an apocalyptic number.

It is an amenable number.

13138825145077 is a deficient number, since it is larger than the sum of its proper divisors (1).

13138825145077 is an equidigital number, since it uses as much as digits as its factorization.

13138825145077 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5644800, while the sum is 55.

The spelling of 13138825145077 in words is "thirteen trillion, one hundred thirty-eight billion, eight hundred twenty-five million, one hundred forty-five thousand, seventy-seven".