Base | Representation |
---|---|
bin | 11101111000000111111001… |
… | …100110110111111111110101 |
3 | 122020020201200102221200211021 |
4 | 131320013321212313333311 |
5 | 114210324422241013044 |
6 | 1143244214403541141 |
7 | 36451226344113031 |
oct | 3570077146677765 |
9 | 566221612850737 |
10 | 131400122204149 |
11 | 3896052a432287 |
12 | 128a228308a7b1 |
13 | 5841c945a82b6 |
14 | 2463b2aad91c1 |
15 | 102d0432e6e84 |
hex | 7781f99b7ff5 |
131400122204149 has 2 divisors, whose sum is σ = 131400122204150. Its totient is φ = 131400122204148.
The previous prime is 131400122204107. The next prime is 131400122204209. The reversal of 131400122204149 is 941402221004131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 94453479563524 + 36946642640625 = 9718718^2 + 6078375^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131400122204149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131400122204849) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65700061102074 + 65700061102075.
It is an arithmetic number, because the mean of its divisors is an integer number (65700061102075).
Almost surely, 2131400122204149 is an apocalyptic number.
It is an amenable number.
131400122204149 is a deficient number, since it is larger than the sum of its proper divisors (1).
131400122204149 is an equidigital number, since it uses as much as digits as its factorization.
131400122204149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 34.
The spelling of 131400122204149 in words is "one hundred thirty-one trillion, four hundred billion, one hundred twenty-two million, two hundred four thousand, one hundred forty-nine".
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