Base | Representation |
---|---|
bin | 1011111100110110011101… |
… | …1100010100000101100111 |
3 | 1201112011202000021200002002 |
4 | 2333031213130110011213 |
5 | 3210241300322342043 |
6 | 43540241245035515 |
7 | 2524223310554216 |
oct | 277154734240547 |
9 | 51464660250062 |
10 | 13140040434023 |
11 | 42067292a0588 |
12 | 1582764b55b9b |
13 | 74413ca36669 |
14 | 335da4b7b07d |
15 | 17bc08be3bb8 |
hex | bf367714167 |
13140040434023 has 2 divisors, whose sum is σ = 13140040434024. Its totient is φ = 13140040434022.
The previous prime is 13140040434019. The next prime is 13140040434029. The reversal of 13140040434023 is 32043404004131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13140040434023 - 22 = 13140040434019 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13140040434029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570020217011 + 6570020217012.
It is an arithmetic number, because the mean of its divisors is an integer number (6570020217012).
Almost surely, 213140040434023 is an apocalyptic number.
13140040434023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140040434023 is an equidigital number, since it uses as much as digits as its factorization.
13140040434023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 13140040434023 its reverse (32043404004131), we get a palindrome (45183444438154).
The spelling of 13140040434023 in words is "thirteen trillion, one hundred forty billion, forty million, four hundred thirty-four thousand, twenty-three".
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