131400414012340 has 24 divisors (see below), whose sum is σ = 301026403010592. Its totient is φ = 47781968731680.

The previous prime is 131400414012311. The next prime is 131400414012353. The reversal of 131400414012340 is 43210414004131.

It is a super-2 number, since 2×131400414012340² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131400414012299 and 131400414012308.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 298637304354 + ... + 298637304793.

It is an arithmetic number, because the mean of its divisors is an integer number (12542766792108).

Almost surely, 2^{131400414012340} is an apocalyptic number.

131400414012340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131400414012340 is an abundant number, since it is smaller than the sum of its proper divisors (169625988998252).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131400414012340 is a wasteful number, since it uses less digits than its factorization.

131400414012340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 597274609167 (or 597274609165 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 131400414012340 its reverse (43210414004131), we get a palindrome (174610828016471).

The spelling of 131400414012340 in words is "one hundred thirty-one trillion, four hundred billion, four hundred fourteen million, twelve thousand, three hundred forty".