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13140100221953 is a prime number
BaseRepresentation
bin1011111100110110101100…
…0000011000110000000001
31201112011220011210012200212
42333031223000120300001
53210241411124100303
643540251222323505
72524224635006105
oct277155300306001
951464804705625
1013140100221953
11420675a0170a1
121582780b89595
1374414c23ac33
14335dacaa1905
1517bc0e0a3ad8
hexbf36b018c01

13140100221953 has 2 divisors, whose sum is σ = 13140100221954. Its totient is φ = 13140100221952.

The previous prime is 13140100221907. The next prime is 13140100222001. The reversal of 13140100221953 is 35912200104131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13063142804209 + 76957417744 = 3614297^2 + 277412^2 .

It is a cyclic number.

It is not a de Polignac number, because 13140100221953 - 26 = 13140100221889 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13140100223953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570050110976 + 6570050110977.

It is an arithmetic number, because the mean of its divisors is an integer number (6570050110977).

Almost surely, 213140100221953 is an apocalyptic number.

It is an amenable number.

13140100221953 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140100221953 is an equidigital number, since it uses as much as digits as its factorization.

13140100221953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 32.

The spelling of 13140100221953 in words is "thirteen trillion, one hundred forty billion, one hundred million, two hundred twenty-one thousand, nine hundred fifty-three".