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1314012400067 is a prime number
BaseRepresentation
bin10011000111110001001…
…111100000100111000011
311122121200210011010111102
4103013301033200213003
5133012044133300232
62443352102005015
7163635311053613
oct23076117404703
94577623133442
101314012400067
114672a681a814
121927b811676b
1396bac158423
144785456ca43
15242a91a7662
hex131f13e09c3

1314012400067 has 2 divisors, whose sum is σ = 1314012400068. Its totient is φ = 1314012400066.

The previous prime is 1314012399983. The next prime is 1314012400069. The reversal of 1314012400067 is 7600042104131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1314012400067 - 220 = 1314011351491 is a prime.

Together with 1314012400069, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1314012400069) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657006200033 + 657006200034.

It is an arithmetic number, because the mean of its divisors is an integer number (657006200034).

Almost surely, 21314012400067 is an apocalyptic number.

1314012400067 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314012400067 is an equidigital number, since it uses as much as digits as its factorization.

1314012400067 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 29.

Adding to 1314012400067 its reverse (7600042104131), we get a palindrome (8914054504198).

The spelling of 1314012400067 in words is "one trillion, three hundred fourteen billion, twelve million, four hundred thousand, sixty-seven".