13140204033301 has 2 divisors, whose sum is σ = 13140204033302. Its totient is φ = 13140204033300.

The previous prime is 13140204033277. The next prime is 13140204033337. The reversal of 13140204033301 is 10333040204131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11090238700401 + 2049965332900 = 3330201^2 + 1431770^2 .

It is a cyclic number.

It is not a de Polignac number, because 13140204033301 - 2⁵ = 13140204033269 is a prime.

It is a super-3 number, since 3×13140204033301³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13140204033391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570102016650 + 6570102016651.

It is an arithmetic number, because the mean of its divisors is an integer number (6570102016651).

Almost surely, 2^{13140204033301} is an apocalyptic number.

It is an amenable number.

13140204033301 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140204033301 is an equidigital number, since it uses as much as digits as its factorization.

13140204033301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13140204033301 its reverse (10333040204131), we get a palindrome (23473244237432).

The spelling of 13140204033301 in words is "thirteen trillion, one hundred forty billion, two hundred four million, thirty-three thousand, three hundred one".