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13140223002241 is a prime number
BaseRepresentation
bin1011111100110111001001…
…0100110000011010000001
31201112012012201211002120221
42333031302110300122001
53210242134042032431
643540311330103041
72524230655430116
oct277156224603201
951465181732527
1013140223002241
114206812357805
1215827b611aa81
1374416b7c94aa
14335dc110290d
1517bc19c58111
hexbf372530681

13140223002241 has 2 divisors, whose sum is σ = 13140223002242. Its totient is φ = 13140223002240.

The previous prime is 13140223002239. The next prime is 13140223002337. The reversal of 13140223002241 is 14220032204131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6835584105025 + 6304638897216 = 2614495^2 + 2510904^2 .

It is a cyclic number.

It is not a de Polignac number, because 13140223002241 - 21 = 13140223002239 is a prime.

Together with 13140223002239, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13140223003241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570111501120 + 6570111501121.

It is an arithmetic number, because the mean of its divisors is an integer number (6570111501121).

Almost surely, 213140223002241 is an apocalyptic number.

It is an amenable number.

13140223002241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140223002241 is an equidigital number, since it uses as much as digits as its factorization.

13140223002241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13140223002241 its reverse (14220032204131), we get a palindrome (27360255206372).

The spelling of 13140223002241 in words is "thirteen trillion, one hundred forty billion, two hundred twenty-three million, two thousand, two hundred forty-one".