131402242010041 has 2 divisors, whose sum is σ = 131402242010042. Its totient is φ = 131402242010040.

The previous prime is 131402242009957. The next prime is 131402242010063. The reversal of 131402242010041 is 140010242204131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110407472190016 + 20994769820025 = 10507496^2 + 4582005^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131402242010041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131402242009988 and 131402242010015.

It is not a weakly prime, because it can be changed into another prime (131405242010041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701121005020 + 65701121005021.

It is an arithmetic number, because the mean of its divisors is an integer number (65701121005021).

Almost surely, 2^{131402242010041} is an apocalyptic number.

It is an amenable number.

131402242010041 is a deficient number, since it is larger than the sum of its proper divisors (1).

131402242010041 is an equidigital number, since it uses as much as digits as its factorization.

131402242010041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 131402242010041 its reverse (140010242204131), we get a palindrome (271412484214172).

The spelling of 131402242010041 in words is "one hundred thirty-one trillion, four hundred two billion, two hundred forty-two million, ten thousand, forty-one".