Base | Representation |
---|---|
bin | 11101111000001001110111… |
… | …111101010010101111001111 |
3 | 122020020221011011201222212102 |
4 | 131320021313331102233033 |
5 | 114210343242423310223 |
6 | 1143245205010425315 |
7 | 36451333024140143 |
oct | 3570116775225717 |
9 | 566227134658772 |
10 | 131402242010063 |
11 | 38961417a688a2 |
12 | 128a2774b9223b |
13 | 584224180c11b |
14 | 2463c8c45d223 |
15 | 102d119472928 |
hex | 778277f52bcf |
131402242010063 has 2 divisors, whose sum is σ = 131402242010064. Its totient is φ = 131402242010062.
The previous prime is 131402242010041. The next prime is 131402242010077. The reversal of 131402242010063 is 360010242204131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131402242010063 - 212 = 131402242005967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131402242000063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701121005031 + 65701121005032.
It is an arithmetic number, because the mean of its divisors is an integer number (65701121005032).
Almost surely, 2131402242010063 is an apocalyptic number.
131402242010063 is a deficient number, since it is larger than the sum of its proper divisors (1).
131402242010063 is an equidigital number, since it uses as much as digits as its factorization.
131402242010063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 131402242010063 its reverse (360010242204131), we get a palindrome (491412484214194).
The spelling of 131402242010063 in words is "one hundred thirty-one trillion, four hundred two billion, two hundred forty-two million, ten thousand, sixty-three".
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