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131402302401397 is a prime number
BaseRepresentation
bin11101111000001001111011…
…100011101010101101110101
3122020020221022101101012012111
4131320021323203222231311
5114210343403403321042
61143245215005051021
736451334356354156
oct3570117343525565
9566227271335174
10131402302401397
1138961449066795
12128a2791256a71
135842251195241
142463c9649d92d
15102d11e901517
hex77827b8eab75

131402302401397 has 2 divisors, whose sum is σ = 131402302401398. Its totient is φ = 131402302401396.

The previous prime is 131402302401379. The next prime is 131402302401407. The reversal of 131402302401397 is 793104203204131.

Together with previous prime (131402302401379) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77648682798801 + 53753619602596 = 8811849^2 + 7331686^2 .

It is a cyclic number.

It is not a de Polignac number, because 131402302401397 - 211 = 131402302399349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131402302401367) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701151200698 + 65701151200699.

It is an arithmetic number, because the mean of its divisors is an integer number (65701151200699).

Almost surely, 2131402302401397 is an apocalyptic number.

It is an amenable number.

131402302401397 is a deficient number, since it is larger than the sum of its proper divisors (1).

131402302401397 is an equidigital number, since it uses as much as digits as its factorization.

131402302401397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108864, while the sum is 40.

The spelling of 131402302401397 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred two million, four hundred one thousand, three hundred ninety-seven".