131402302401407 has 2 divisors, whose sum is σ = 131402302401408. Its totient is φ = 131402302401406.

The previous prime is 131402302401397. The next prime is 131402302401427. The reversal of 131402302401407 is 704104203204131.

It is a weak prime.

It is an emirp because it is prime and its reverse (704104203204131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131402302401407 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131402302401427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701151200703 + 65701151200704.

It is an arithmetic number, because the mean of its divisors is an integer number (65701151200704).

Almost surely, 2^{131402302401407} is an apocalyptic number.

131402302401407 is a deficient number, since it is larger than the sum of its proper divisors (1).

131402302401407 is an equidigital number, since it uses as much as digits as its factorization.

131402302401407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16128, while the sum is 32.

Adding to 131402302401407 its reverse (704104203204131), we get a palindrome (835506505605538).

The spelling of 131402302401407 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred two million, four hundred one thousand, four hundred seven".