Base | Representation |
---|---|
bin | 1011111100110111001011… |
… | …0111011110110101101111 |
3 | 1201112012020100221120200021 |
4 | 2333031302313132311233 |
5 | 3210242143404332302 |
6 | 43540312253143011 |
7 | 2524231126002535 |
oct | 277156267366557 |
9 | 51465210846607 |
10 | 13140232105327 |
11 | 4206817505018 |
12 | 15827b918aa67 |
13 | 744170665a32 |
14 | 335dc23d2155 |
15 | 17bc1a955437 |
hex | bf372dded6f |
13140232105327 has 2 divisors, whose sum is σ = 13140232105328. Its totient is φ = 13140232105326.
The previous prime is 13140232105309. The next prime is 13140232105367. The reversal of 13140232105327 is 72350123204131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13140232105327 - 215 = 13140232072559 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13140232105292 and 13140232105301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13140232105367) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570116052663 + 6570116052664.
It is an arithmetic number, because the mean of its divisors is an integer number (6570116052664).
Almost surely, 213140232105327 is an apocalyptic number.
13140232105327 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140232105327 is an equidigital number, since it uses as much as digits as its factorization.
13140232105327 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30240, while the sum is 34.
Adding to 13140232105327 its reverse (72350123204131), we get a palindrome (85490355309458).
The spelling of 13140232105327 in words is "thirteen trillion, one hundred forty billion, two hundred thirty-two million, one hundred five thousand, three hundred twenty-seven".
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