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131402354135293 is a prime number
BaseRepresentation
bin11101111000001001111110…
…101001000001000011111101
3122020020221102222201112202201
4131320021332221001003331
5114210344010124312133
61143245224053551501
736451335555162643
oct3570117651010375
9566227388645681
10131402354135293
113896147529117a
12128a27a6645591
13584225bb09907
142463c9d2c9193
15102d12421ed7d
hex77827ea410fd

131402354135293 has 2 divisors, whose sum is σ = 131402354135294. Its totient is φ = 131402354135292.

The previous prime is 131402354135291. The next prime is 131402354135323. The reversal of 131402354135293 is 392531453204131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127877490573849 + 3524863561444 = 11308293^2 + 1877462^2 .

It is a cyclic number.

It is not a de Polignac number, because 131402354135293 - 21 = 131402354135291 is a prime.

Together with 131402354135291, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131402354135291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701177067646 + 65701177067647.

It is an arithmetic number, because the mean of its divisors is an integer number (65701177067647).

Almost surely, 2131402354135293 is an apocalyptic number.

It is an amenable number.

131402354135293 is a deficient number, since it is larger than the sum of its proper divisors (1).

131402354135293 is an equidigital number, since it uses as much as digits as its factorization.

131402354135293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1166400, while the sum is 46.

The spelling of 131402354135293 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred fifty-four million, one hundred thirty-five thousand, two hundred ninety-three".