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13140240037 is a prime number
BaseRepresentation
bin11000011110011100…
…00010011010100101
31020220202200100121221
430033032002122211
5203402400140122
610011520540341
7643425124501
oct141716023245
936822610557
1013140240037
115633360911
1226687816b1
131315464382
148c9233301
1551d9046c7
hex30f3826a5

13140240037 has 2 divisors, whose sum is σ = 13140240038. Its totient is φ = 13140240036.

The previous prime is 13140239999. The next prime is 13140240107. The reversal of 13140240037 is 73004204131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12821938756 + 318301281 = 113234^2 + 17841^2 .

It is a cyclic number.

It is not a de Polignac number, because 13140240037 - 231 = 10992756389 is a prime.

It is a super-2 number, since 2×131402400372 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13140239993 and 13140240020.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13140240137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570120018 + 6570120019.

It is an arithmetic number, because the mean of its divisors is an integer number (6570120019).

Almost surely, 213140240037 is an apocalyptic number.

It is an amenable number.

13140240037 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140240037 is an equidigital number, since it uses as much as digits as its factorization.

13140240037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 25.

Adding to 13140240037 its reverse (73004204131), we get a palindrome (86144444168).

The spelling of 13140240037 in words is "thirteen billion, one hundred forty million, two hundred forty thousand, thirty-seven".